Question

25) For a gaseous reaction at 298K, Kp is 10-6. The change in standard Gibbs free energy in KJ mol-1)
will be
a) 25.49
b) 34.23
c) 40.17
d) 28.92​

Answer 1

Answer:

9114

Explanation:

ΔH  

dissolution

​

=ΔH  

(ionisation)

​

+ΔH  

(hydration)

​

=778−774.3

=3.7kJmol  

−1

=3700Jmol  

−1

 

ΔS  

dissolution

​

=43JK  

−1

 

∴ΔG  

dissolution

​

=ΔH−TΔS

=3700−298×43=−9114J

ΔG=−9.114kJ