Question

25 G of a sample contains 50% MgCl2 and 50% mgso4 the percent of MG in the mixture is​

Answer 1

Given weight of mixture = 25g

Molecular weight of mixture = 120 +95 =215g

Amount of magnesium in mixture = 24/215 * 25 = 2.8g

% of Mg in mixture = 2.8/25 * 100 = 11.16

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Answer 2

Answer:

Given weight of mixture = 25g

Molecular weight of mixture = 120 +95 =215g

Amount of magnesium in mixture = 24/215 * 25 = 2.8g

% of Mg in mixture = 2.8/25 * 100 = 11.16

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