25 g of a solute of molar mass 250 g is dissolved in water to obtain 100mL of the solution with density 1.25 g/mL. The molality of the solution is
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Explanation:
It is given tht 25 gm of solute of molar mass 250 is dissolved in 100ml of water
--> No.of moles of solute present in the solution is 25÷250 = 0.1 mole
And Since , density of the solution is 1.25 gm /ml
--> mass of 100 ml solvent i.e. water will be 100× 1.25 gm = 125 gm
Therefore molality (m ) = (0.1×1000 )÷(125) = 0.8.
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Explanation:
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