25 gm of ice is converted into water at 0 ºC by supply of heat, then the increase in entropy will be
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The change in entropy would be given as ΔS=ΔS1+ΔS2 ΔS1 is to melt the ice and ΔS2 is to rise the temperature. Thus we get ΔS=TmL+m∫T1T2TdT
ΔS=2731×80+1×ln273313=0.28+0.13=0.41 cal/oC
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