Science, asked by MANAVALAN, 10 months ago

25 gram of Nitrogen reacts with hydrogen to form Ammonia find out the limiting reagent and calculate the amount of ammonia formed

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Answered by Anonymous

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ʟɪᴍɪᴛɪɴɢ ʀᴇᴀɢᴇɴᴛ ɪɴ ᴀ ʀᴇᴀᴄᴛɪᴏɴ ɪs ᴛʜᴇ ᴏɴᴇ ᴡʜɪᴄʜ ɪs ᴄᴏɴsᴜᴍᴇᴅ ᴛᴏᴛᴀʟʟʏ ʙᴇғᴏʀᴇ ᴛʜᴇ ᴛᴏᴛᴀʟ ᴄᴏɴsᴜᴍᴘᴛɪᴏɴ ᴏғ ᴀɴʏ ᴏᴛʜᴇʀ ʀᴇᴀᴄᴛᴀɴᴛ ᴀɴᴅ ғᴏʀ ᴛʜᴇ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴ ᴏғ ᴛʜᴇ sᴀᴍᴇ, ɪᴛ ɪs ʙᴇᴛᴛᴇʀ ᴛᴏ ᴅᴏ ᴛʜᴇ ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴs ᴏɴ ᴍᴏʟᴇ ʙᴀsɪs.

sᴏ, ғᴏʀ ᴛʜᴇ ɢɪᴠᴇɴ ᴄᴏɴᴅɪᴛɪᴏɴ ғɪʀsᴛ ʟᴇᴛ ᴡᴇ ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ɴᴜᴍʙᴇʀ ᴏғ ᴍᴏʟᴇs ᴏғ ᴇᴀᴄʜ ʀᴇᴀᴄᴛᴀɴᴛ-

ᴀs ᴡᴇ ᴋɴᴏᴡ,

ɴᴜᴍʙᴇʀ ᴏғ ᴍᴏʟᴇs = ᴡᴇɪɢʜᴛ (ɪɴ ɢʀᴀᴍs)/ᴍᴏʟᴇᴄᴜʟᴀʀ ᴡᴛ.

ᴍᴏʟ. ᴡᴛ. ᴏғ ɴ2- 28

ᴍᴏʟ. ᴡᴛ. ᴏғ ʜ2- 2

sɪɴᴄᴇ, ᴡᴇ ʜᴀᴠᴇ 28ɢ ᴏғ ɴ2 & 12ɢ ᴏғ ʜ2

ᴛʜᴜs,

ɴᴏ. ᴏғ ᴍᴏʟᴇs ᴏғ ɴ2- 28/28 = 1 ᴍᴏʟᴇ

& ɴᴏ. ᴏғ ᴍᴏʟᴇs ᴏғ ʜ2- 12/2 = 6 ᴍᴏʟᴇs

ɴᴏᴡ, ғʀᴏᴍ ᴛʜᴇ sᴛᴏɪᴄʜɪᴏᴍᴇᴛʀʏ ᴏғ ᴛʜᴇ ʀᴇᴀᴄᴛɪᴏɴ

ɴ2 + 3ʜ2 → 2ɴʜ3

ᴡᴇ ᴄᴀɴ sᴇᴇ ᴛʜᴀᴛ, ғᴏʀ 1 ᴍᴏʟᴇ ᴏғ ɴ2 ᴡᴇ ʀᴇϙᴜɪʀᴇ 3 ᴍᴏʟᴇs ᴏғ ʜ2 ᴛᴏ ᴘʀᴏᴅᴜᴄᴇ 2 ᴍᴏʟᴇs ᴏғ ɴʜ3 ᴀɴᴅ ʜᴇʀᴇ ғᴏʀ 1 ᴍᴏʟᴇ ᴏғ ɴ2 ᴡᴇ ʜᴀᴠᴇ 6 ᴍᴏʟᴇs ᴏғ ʜ2 ɪ.ᴇ. ᴡᴇ ʜᴀᴠᴇ 3 ᴍᴏʟᴇs ᴏғ ᴇxᴄᴇss ʜ2 ᴡʜɪᴄʜ ᴡɪʟʟ ʙᴇ ᴜɴᴜsᴇᴅ. ᴛʜᴜs ғᴏʀ ᴛʜᴇ ɢɪᴠᴇɴ ᴄᴀsᴇ ɴ2 ᴡɪʟʟ ʙᴇ ᴛʜᴇ ʟɪᴍɪᴛɪɴɢ ʀᴇᴀɢᴇɴᴛ.

ᴛʜᴀɴᴋ ʏᴏᴜ.

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25 gram of Nitrogen reacts with hydrogen to form Ammonia find out the limiting reagent and calculate the amount of ammonia formed​

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25 gram of Nitrogen reacts with hydrogen to form Ammonia find out the limiting reagent and calculate the amount of ammonia formed