Question

25 grams of calcium carbonate is heated find the number of moles volume at STP mass and number of molecules of carbon dioxide producing chemical reaction​

Answer 1

Answer:

11 g mass and 1.5 * 10^23 no of molecules of co2

Explanation:

caco3 gives cao and co2

moles of caco3=25/100=0.25mol

1 mole caco3 reacts with 1 mole co2

therefore, moles of co2=0.25 mol

=0.25 * 44=11g and =0.25 * avagadro no =0.25*6 *10^23=1.5*10^23