Question

25 ) How much force is required to stop a vehicle of mass 1000 kg
running on a road with coefficient of friction between the tyres and the
road is 0.4? | टायर आणि रस्ता यांच्यामध्ये घर्षण गुणकाची किंमत ०.४ असताना रस्त्यावर
धावणाऱ्या १००० kg वस्तुमानाच्या वाहनाला थांबवण्यासाठी किती बल लागेल?
A A) 3000 kg
B ) 450 kg
C) 350 kg
O
D D)400 kg​

Answer 1

sorry I didn't know you answer

Answer 2

Answer:

4000 N

Step-by-step explanation:

We know that,

F= uN where,

F= force

u=  coefficient of friction

N= Normal force

Here, F= 0.4 * N

Here N = ma

m= 1000 kg and a= 10m/s^2 or 9.8 m/s^2

N= 1000 * 10 = 10000 N

Hence,

F = 0.4 * 10000

  = 4000 N

Hope it helps !