Question

25. Hydrogen sulphide gas burns in oxygen to yield
12.8 g of sulphur dioxide gas as under :
2H S + 302 → 2H2O + 2S02
Calculate the volume of hydrogen sulphide at STP.
Also, calculate the volume of oxygen required at STP.
which will complete the combustion of hydrogen sulphide
determined in litres.
​

Answer 1

2H²S + 30² => 2H²O + 2SO²

2V 3V 2V

128g of SO² gives = 2×22.4 litre

Hence,

12.8g of SO² gives = 2×22.4×12.8 = 4.48 litres of hydrogen sulphide

2×22.4 litre H²S Requires oxygen= 3×22.4 litre

Therefore,

4.48 litres hydrogen sulphide will require 6.72 litres of Oxygen