Question

25. If -4 is a root of the equation x ²+p x - 4 = 0 and the equation x² + px + q = 0 has equal roots then

find the value of p and q.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Put x = -4

Put x = -4(-4)2 +p (-4) -4 =0

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =0

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0-4p = -12

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0-4p = -12p = 3

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0-4p = -12p = 3similarly,

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0-4p = -12p = 3similarly,(-4)2 + 3 (-4) +q =0

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0-4p = -12p = 3similarly,(-4)2 + 3 (-4) +q =016 - 12 +q =0

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0-4p = -12p = 3similarly,(-4)2 + 3 (-4) +q =016 - 12 +q =04 + q = 0

Put x = -4(-4)2 +p (-4) -4 =016 -4p -4 =012 -4p =0-4p = -12p = 3similarly,(-4)2 + 3 (-4) +q =016 - 12 +q =04 + q = 0q = -4