Question

(25) If a linear equation has solutions (-2, 2), (0, 0) and (2,-2), then it is of the form O a) y - x = 0 O b) x + y = 0 OCy c)-2x + y = 0 O d) -x + 2y = 0​

Answer 1

Answer:

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Answer 2

Given:

If a linear equation has solutions (-2, 2), (0, 0) and (2,-2)

To Find:

then it is of the form

a) y - x = 0 b) x + y = 0 c)-2x + y = 0 d) -x + 2y = 0​

Solution:

It is given that a linear equation has solutions as  (-2, 2), (0, 0) and (2,-2) then we need to find the equation, we can use the solutions as points or coordinates and then the equation could be found by two-point formula, that is with points (x1,x2) (y1,y2)

$(y-y_{1})=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})$

Now taking the points as (-2,2) and (0,0) the equation will be,

$y-0=\frac{2-0}{-2-0}(x-0)\\y=-x\\x+y=0$

so the equation passing through these two points or say the solutions for the equation is x+y=0

Hence, the correct option is (b).