Question

25. If a number x is chosen at random from the number
-3, -2, -1,0, 1, 2, 3. What is probability that x^2≤4?​

Answer 1

Let's verify the solutions.

$x=3,-3 \implies 9\leq 4\: \text{ [False] }$

$x=2,-2 \implies 4 \leq 4 \text{ [True] }$

$x=1,-1 \implies 1 \leq 4 \: \text{[True]}$

$x=0 \implies 0\leq 4 \: \text{ [True] }$

$\text{Probability} = \dfrac{ \text{Certain Events} }{ \text{Total Events} }$

It's 5 solutions between 7 numbers. The probability of choosing one number, which is a solution, is equal to $\dfrac{5}{7}$.

Answer 2

Given :-

number = x

To Find :-

Probability

Solution :-

$\large \sf x = 2,-2 = 4 \leq 9$

x = 1,-1 = 1 $\leq$ 9

x = 0 = $0 \leq 9$

P(E) = 3/7