Math, asked by BrainlyProfession, 3 months ago

25. If a number x is chosen at random from the number
-3, -2, -1,0, 1, 2, 3. What is probability that x^2≤4?


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Answers

Answered by anilsah3204
2

Answer:

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Step-by-step explanation:

Total possible outcomes = 5 {-2,-1,0,1,2}

Favourable outcomes = 3 {-1,0,1}(x^2<2)

If X is -2 , then x^2 = 4 which is greater than 2. (-2)^2>2= 4>2. So X can't be-2.

Similarly, X can't be 2.

But it can be -1,0 or 1.

So , P(E) = 3/5.

Answered by princesshinata
1

Answer:

Total possible outcomes = 5 {-2,-1,0,1,2}

Favourable outcomes = 3 {-1,0,1}(x^2<2)

If X is -2 , then x^2 = 4 which is greater than 2. (-2)^2>2= 4>2. So X can't be-2.

Similarly, X can't be 2.

But it can be -1,0 or 1.

So , P(E) = 3/5.

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