Question

25. If cos 0 thita =
8/17
then find the value of tan 0 thita​

Answer 1

The answer is 15/8.

Hope it helps...❤️

Answer 2

Answer:

Given that,

       $cos \alpha = \frac{8}{17}$             ( θ will be taken as α )

We know that,

       $sec^{2} \alpha = 1+tan^{2} \alpha \\\\=> \frac{1}{cos^{2}\alpha } = 1 + tan^{2} \alpha \\\\=> tan\alpha = \sqrt{\frac{1}{cos^2\alpha } -1 }\\\\cos\alpha = \frac{8}{17} \\\\Now,\\ tan\alpha = \sqrt{\frac{1-cos^2\alpha }{cos^2\alpha } } \\\\ tan\alpha = \sqrt{\frac{1-(\frac{8}{17}) ^2 }{(\frac{8}{17}) ^2} }\\\\ tan\alpha = \sqrt{\frac{225}{64} } \\\\ tan\alpha = \frac{15}{8 } (Ans.)$

           Hope it helps

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