25. If log 2 = 0.3010, log 3 = 0.4771 and log 7 = 0.8451,
then find the values of log 210.
Answers
Answered by
5
Answer: 2.3222
Let : log₁₀2 = x
And let : log₁₀3 = y, log₁₀7 = z
Prime factorization of 210 is first.
log₁₀210 = log₁₀2×3×5×7
→ log₁₀10×3×7
→ log₁₀10 + log₁₀3 + log₁₀7 (Logarithm)
→ 1 + x + z
→ 2.3222
Answered by
2
take the general base as 10
log (5.6.7)
log5+log6+log7
log10/2 +log6 +log7
log10-log2+log6+log7
log10-log2+log2+log3+log7
1+0.4772+0.8451
2.3222
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