Question

25. If y+1 is a factor of the
polynomial 2y2+ky, then kis
equal to
O(a) -2
O (b) - 3
O (c) 4
O (d) 2​

Answer 1

Correct question:

If (y+1) is a factor of the polynomial 2y² + ky, then k is equal to

(a) - 2

(b) - 3

(c) 4

(d) 2

Answer:

• Option (d) 2 is the correct answer

Given:

Polynomial = P(y) = 2y² + ky

(y + 1) is the factor of the polynomial P(y)

To find:

The value of k for which y+1 is a factor of the polynomial P(y)

Now,

As, (y + 1) = 0

⇒ y = (-1)

And (-1) is one zero of the polynomial P(y), which means P(-1) = 0

P(-1) = 2(-1)² + k(-1) = 0

⇒ 2 * 1 - k = 0

∴ 2 = k

Hence,

For value of k = 2, (y + 1) is the factor of the polynomial P(y) = 2y² + ky.

• Polynomial = 2y² + 2y

Answer 2

Answer:

$\bigstar$ Given $\bigstar$

✍️ If y + 1 is a factor of the polynomial is 2y²+ky.

$\bigstar$ To Find $\bigstar$

✍️ The value of k.

➡️ Solution ⬅️

Let the y = -1

Then,

=> p(y) = 2y² + ky

=> p(-1) = 2(-1)² + k(-1) = 0

=> 2(1) - k = 0

=> 2 - k = 0

=> k = 2

Therefore, the value of k is 2.

Step-by-step explanation:

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