Question

25) In an arithmetic progression sum of first 3 consecutive terms is 15 and them
product is 105. Find such numbers.​

Answer 1

Answer:

3,5,7

Step-by-step explanation:

a-d+a+a+d=15

3a=15

a=5

(5-d)(5)(5+d)=105

(5-d)(5+d)=21

25-d^2=21

d^2=4

d=2