Chemistry, asked by Patelhamza4033, 10 months ago

25. In the electrochemical cell :
Zn|ZnSO₄(0.01M)||CuSO₄(1.0 M)|Cu, the emf of thisDaniel cell is E₁. When the concentration of ZnSO₄is changed to 1.0 M and that of CuSO₄ changed to0.01 M, the emf changes to E₂. From the following,which one is the relationship between E₁ and E₂?
(Given, RT/F = 0.059)
(1) E₁ = E₂ (2) E₁ < E₂
(3) E₁ > E₂ (4) E₂ = 0 ≠ E₁

Answers

Answered by jaswasri2006
0

 \huge \tt e1 &gt; e2

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