Question

25) In the figure < PQR= 42°, <QRP =
61°. Find < QSR°

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Answer 1

Answer:

is there any figure of this question

I think we have to find < QPR in the given question...

Answer 2

Answer:

((((((IT IS <QPR⁰)))))

<QPR⁰= 77⁰

Step-by-step explanation:

NOW,

<PQR+<QRP=42+61 =103⁰

#sum of angles of a triangle is 180⁰

#<QPR=180⁰-103⁰

#<QPR=77⁰

HOPE IT IS HELPFUL