Question

25. In the given figure, AB || CD || EF, ABG = 110°, GCD = 100°
and BGC = xº. Then, X = ?​

Answer 1

<BGF=<ABG=110°( alternate angles)

<BGE=180°- <BGF

=180°-110°

=70°

<CGE=<DCG=100°(alternate angles)

<CGF=180°- <CGE

=180°-100°

=80°

<BGE+<BGC+<CGF=180°(Sum of all

angles on a straight line)

or, 70°+x+80°=180°

or, x=180°-150°

or, x=30°

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Hope this helps you.......