25. In triangle ABC, BC=AB and /_
B=80°. Then/_A is equal to:
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/_B=80°
Here AB = BC then /_A = /_C
/_A+/_B+/_C=180° (the sum of the three angles of a triangle is 180 degree)
/_A+80°+/_C =180°
/_A+/_C=180-80
/_A+/_C=100
/_A=50 /_C= 50 here /_A = /_C
so the answer is angle A=50°
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