Question

-25 के 7 गुणजो का योग क्या होगा ​

Answer 1

What will be the sum of 7 multiples of -25?

a = 25

d = 25

n = 7

$s_{n} = \frac{n}{2} (2a + (n - 1))d$

$= \frac{7}{2} (2(25) + (7 - 1))25$

$= \frac{7}{2} (50 + 150)$

$= \frac{7}{2} (200)$

$= 7(100)$

$= 700$

Answer 2

Answer:

What will be the sum of 7 multiples of -25?

a = 25

d = 25

n = 7

s_{n} = \frac{n}{2} (2a + (n - 1))ds

n

=

2

n

(2a+(n−1))d

= \frac{7}{2} (2(25) + (7 - 1))25=

2

7

(2(25)+(7−1))25

= \frac{7}{2} (50 + 150)=

2

7

(50+150)

= \frac{7}{2} (200)=

2

7

(200)

= 7(100)=7(100)

= 700=700