Question

25 kg crate , starting from rest at the top , slides

down a plane that makes an angle of 30° with the

horizontal.When it reaches the bottom of the 10 m

long slide , its velocity is 8 m / s. The workdone

by the force of friction is closest to a value of​

Answer 1

Answer:

Mass of the block m=8 kg

Acceleration of the block a=0.4m/s

2

Since the block is sliding down the plane, so friction force acts backwards as shown.

Equation of motion along the inclined plane :

Step-by-step explanation:

ma=mgsin30

o

−f

We get f=mgsin30

o

−ma

∴ f=(8)(10)(0.5)−(8)(0.4)

⟹f=36.8 N

solution