Question

25 kg of sand is deposited each second on a conveyor belt moving at 10m/s. The extra power required to maintain the belt in motion is

Answer 1

Answer:

F = rate of change of mass × velocity change

F = (5 kg/s)(6 m/s)

F = 30 N

P = force × rate of displacement

P = Fv = (30 N)(6 m/s)

P = 180 W

Answer 2

According to this question

$\text\blue{Force = mass × Rate }$

$\implies$ 25kg × 10m/s

$\implies$ 250N

$\text\blue{Power = Force × Rate\: of \:displacement }$

$\implies$ 250N × 10m/s

$\implies$ 2500 W ..ans...