25. Lengths of the outer edges of a closed box
are respectively 25 cm, 23 cm and 18 cm.
If thickness of the wood be 2 cm then, find (i) the total internal surface and
090
the cost of painting the internal surface at the rate of 50 paise
Reas
Answers
Answered by
5
Answer:
For wooden box
External length=25 cm
External breath=21 cm
And,External height=13 cm
So,external volume=(25×21×13)cm^3=6825cm^3
Thickness=1.5 cm
So,Internal length=25-(1.5×2)=22cm
Internal breadth=21-(1.5×2)=18cm
Internal height=13-(1.5×2)=10cm
So,Internal volume=(22×18×10)cm^3=3960cm^2
1) Now,Volume of wood=External volume-Internal volume
=6825-3960=2865cm^3
2) Rate=Rs.1.50 per cm^3
And,volume=2865cm^3
So,Cost=Rs.(2865×1.50)=Rs.4297.5
3) Volume of cube=(side)^3=(5)^3cm^3=125cm^3
No. of cube=Internal volume/volume of 1 cube
=(3960/125)=31.68cubes
Step-by-step explanation:
please do follow me
Similar questions