Question

25 liters of 70% hcl solution is mixed with x liters of 40% hcl solution to make a 50% hcl solution. Find the amount of 40% hcl solution added.

Answer 1

Answer: 50 Liters

Explanation: According to the neutralization law,

$M_1V_1+M_2V_2=M_3V_3$

where,

$M_1$ = Concentration of HCl solution = 70%

$V_1$ = volume of HCl solution = ?25 L

$M_2$ =  Concentration of another HCl solution = 40%

$V_2$ = volume of another HCl solution = x L

$M_1$ = Concentration of resulting HCl solution = 50%

$V_1$ = volume of resulting HCl solution = 25 L +x L

Now put all the given values in the above law, we get the volume of NaOH solution.

$70\%\times 25L+40\%\times xL=50\%\times (25+x)L$

$x=50 L$

Therefore, the amount of 40% hcl solution added is 50L.