Question

25 ml Ba(OH)2, solution is neutralized by 35 ml 0.1 M HCl, what will be molarity of Ba(OH)2,
solution ?
(A) 0.42
(B) 0.21
(C) 0.07
(D) 0.14​

Answer 1

Answer:➡Reaction :-

Ba(OH)2 + 2HCl--------> BaCl2 + 2H2O

➡Explanation :-

M1V1/n1 = M2V2/n2

Where,

M1 and M2 are respectively, the moralities of Ba(OH)2 & HCl solution.

V1 and V2 are Volumes of Ba(OH)2 & HCl solutions.

n2 = stolchiometric coefficient of HCl = 2

Therefore,

➡Morality of barium hydroxide solution is M1 = ( M2V2/n2) × ( n1/v1)

=( 0.1 × 35/2) × (1/25)

= 0.07M...

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Step-by-step explanation:

Answer 2

Answer:

option d

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