Question

25 ml of 3.0M HNO3 are mixed with 75 ml of 4.0M HNO3. If the volumes are additive, the molarity of the final mixture would be

Answer 1

Answer:- Molarity of the mixture solution is 3.75M.

Solution:- Volume is an additive property so the volume of the mixture would be the sum of the volumes of two solutions of the acid being added together.

We could easily solve this problem using dilution equation:

$M_1V_1+M_2V_2=MV$

Where, M and V are the molarity and volume of the mixture.

Let's plug in the values in the equation:

3.0(25) + 4.0(75) = M(25+75)

75 + 300 = M(100)

375 = M(100)

$M=\frac{375}{100}$

M = 3.75

So, the molarity of the mixture solution is 3.75M.

Answer 2

Answer:

3.0(25) + 4.0(75) = M(25+75)

75 + 300 = M(100)

375 = M(100)

M=\frac{375}{100}

M = 3.75

The final mixture will be =3.75