25 ml of a solution of barium hydroxide on titration with a 0.1M sol. of HCL gave a titre value of 35ml.The molarity of barium hydroxide sol is.
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Answered by
113
Hi friend,
# 0.07M
➡Reaction :-
Ba(OH)2 + 2HCl--------> BaCl2 + 2H2O
➡Explanation :-
M1V1/n1 = M2V2/n2
Where,
M1 and M2 are respectively, the moralities of Ba(OH)2 & HCl solution.
V1 and V2 are Volumes of Ba(OH)2 & HCl solutions.
n2 = stolchiometric coefficient of HCl = 2
Therefore,
➡Morality of barium hydroxide solution is M1 = ( M2V2/n2) × ( n1/v1)
=( 0.1 × 35/2) × (1/25)
= 0.07M...i hope it helps you
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# 0.07M
➡Reaction :-
Ba(OH)2 + 2HCl--------> BaCl2 + 2H2O
➡Explanation :-
M1V1/n1 = M2V2/n2
Where,
M1 and M2 are respectively, the moralities of Ba(OH)2 & HCl solution.
V1 and V2 are Volumes of Ba(OH)2 & HCl solutions.
n2 = stolchiometric coefficient of HCl = 2
Therefore,
➡Morality of barium hydroxide solution is M1 = ( M2V2/n2) × ( n1/v1)
=( 0.1 × 35/2) × (1/25)
= 0.07M...i hope it helps you
==============================
Mark me as a brainliest
Answered by
26
Answer:0.07
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