Question

25 numbers were recorded and their average was calculated as 50.6. Later it was found that three numbers 29, 35, and 72 were wrongly taken as 92, 53 and 27 respectively, and one number 58 ws inadvertently left out from being recorded. What is the correct average of all the numbers?

Answer 1

Answer:

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Answer 2

Given

AVERAGE OF $25$ NO. $=50.6$

Now doing addition of $25$ NO. we get

$25*50.6=1256$

so the addition right no. is given by = $29+35+72= 136$

and wrong no. is $92+53+27 = 172$

∴ difference is $=36$

extra will be $=58$

then sum of usual no. is  $= 1265-58 = 1149$

average is given by $1149/25 = 45.96$