Math, asked by shwetast9, 5 months ago

25. O is centre of the circle OMAB(chords) then prove that AM=MB

Answers

Answered by zohammaaz

1

Step-by-step explanation:

OA is the radius of the circle

Perpendicular drawn from centre to a chord bisects the chord.

Therefore AM=

2

1

AB

AM=10cm

Thus, triangle OMA is right angled triangled at ∠OMA.

∠OMA=90

∘

.

By Pythagoras theorem,

OA

2

=OM

2

+MA

2

OA=

OM

2

+MA

2

OA=

(2

11

)

2

+10

2

OA=

144

cm

OA=12cm

Radius of a circle is 12cm

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