CBSE BOARD XII, asked by anwar5292, 1 year ago

25[P]. Four point charges qA-2HC
qp=-5uc, qc 2uc and qp=-5uc are
located at the corners of a square
ABCD of side 10cm. What is the force
on a charge of luc placed at the
centre of the square?​

Answers

Answered by abhinavak2005
0

Answer:

The given figure shows a square of side 10 cm with four charges placed at its corners. O is the centre of the square. Where, (Sides) AB = BC = CD = AD = 10 cm (Diagonals) AC = BD = 10√2 cm AO = OC = DO = OB = 5√2 cm A charge of amount 1μC is placed at point O. Force of repulsion between charges placed at corner A and centre O is equal in magnitude but opposite in direction relative to the force of repulsion between the charges placed at corner C and centre O. Hence, they will cancel each other. Similarly, force of attraction between charges placed at corner B and centre O is equal in magnitude but opposite in direction relative to the force of attraction between the charges placed at corner D and centre O. Hence, they will also cancel each other. Therefore, net force caused by the four charges placed at the corner of the square on 1 μC charge at centre O is zero.Read more on Sarthaks.com - https://www.sarthaks.com/18165/four-point-charges-qb-c-qc-c-and-qd-c-are-located-at-the-corners-of-square-abcd-of-side-10-cm

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