Question

25 point..........



A disc is rolling on a level surface, find the ratio of kinetic energy due to translational motion to
total energy of the disc.
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Answer 1

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➡️LET THE sphere have mass M and linear velocity v and angular velocity w and radius r.

Translation kinetic energy=1/2mv^2

Rotational kinetic energy=1/2Iw^2

=1/2*2/5*mv^2

=1/2*2/5*mv^2

Ratio=(1/2mv^2)/(2/10mv^2)

=10/4

=5/2

$\mathbb{\huge{\blue{HOPE.IT.HELPS}}}$

Answer 2

$\huge\red{Answer}$

Translation kinetic energy=1/2mv²

Rotational kinetic energy=1/2Iw²

=1/2×2/5×mv²

=1/2×2/5×mv²

Ratio=(1/2mv²)/(2/10mv²)

=10/4

=5/2

HOPE IT HELPS YOU !!