Question

(25 Points) Answer this Physiscs Question

15th Qstn

Answer 1

Hey!

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Length of the wire ( L ) = 50 cm = 0.5 m
Cross sectional area (A) = 1 mm^2 = 1 × 10^-6
Current (I) = 4 A
Battery voltage (V)= 2 V
Resistivity = ?

We know,

First find resistance,

R = V / I = 2/4 = 0.5 Ohm

Resistivity (Rho) = R × A / L

= 0.5 × 1 × 10^-6 / 0.5

= 0.5 × 10^-6 / 0.5

= 10^-6 Ohm m

Option C is correct.
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Hope it helps...!!!

Answer 2

Hey friends!!

Here is your answer↓

It is given that:-
Length of conductor→50cm=0.5m.
Area of cross-section→1mm²=1×10^-6m².
Current=4A.
Battery voltage=2V.
Resistivity=?¿.

First find resistance:-
Resistance=V/I
=2/4 = 0.5Ω.

Resistivity =R×A/L.

=(0.5 × 1×10^-6 /0.5) Ω.m

= (0.5×10^-6/0.5)Ω.m

= 10^-6Ω.m

=1×10^-6 Ω.m

Therefore, option C is correct.

☺☺☺Hope it is helpful for you ✌✌✌.