25 points question
Oxygen is present in a 1-litre flask at a pressure of 7.6×10^-10 mm of Hg at 0℃. Calculate the number of oxygen molecules in the flask.
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First we should calculate the number of moles of the gas under the given condition by the relation
PV = nRT
Here P = 7.6 * 10^(-10) mm Hg
= 7.6 *10^(-10)/760 atm. = 1 * 10^(-12) atm. = 10^(-12) atm.
V = 1 litre
T = 273 + 0 = 273K
R = 0.082 litre atm./K/mol
Putting the values in equation
n = PV/RT = [10^(-12) * 1]/[0.082 *273] moles
now since 1 mole = 6.022 * 10^(23) molecules
[10^(-12)]/[0.082 *273] moles
= 6.023 *10^23 *10^(-12)/[0.082 *273] molecules
= 2.7 * 10^10 molecules
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PV = nRT
Here P = 7.6 * 10^(-10) mm Hg
= 7.6 *10^(-10)/760 atm. = 1 * 10^(-12) atm. = 10^(-12) atm.
V = 1 litre
T = 273 + 0 = 273K
R = 0.082 litre atm./K/mol
Putting the values in equation
n = PV/RT = [10^(-12) * 1]/[0.082 *273] moles
now since 1 mole = 6.022 * 10^(23) molecules
[10^(-12)]/[0.082 *273] moles
= 6.023 *10^23 *10^(-12)/[0.082 *273] molecules
= 2.7 * 10^10 molecules
HOPE IT HELPS
Please mark this answer as a brainlist answer if you like the answer please
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