Question

25 points
Solve for x:
$\sqrt{3} x {}^{2} - 2 \sqrt{2} x - 2 \sqrt{3} = 0$
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Answer 1

√3 x² - 2√2 x - 2√3 = 0

Multiplying √3 and 2√3 = 6

now, split this in such a way that it's sum of difference will be -2√2

i.e. -3√2 +√2 = -2√2

√3 x²-3√2x +√2x -2√3 =0

=√3x(x -√6) +√2(x -√6) =0

=(x-√6)(√3x +√2) =0

So, (x-√6)=0 or (√3x +√2) =0

x = √6 or x= -√(2/3)= -√6/3

thanks

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Answer 2

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