Question

25 points ..
Solve it please ....
Question 19

Answer 1

hope this helps you☺️

Answer 2

$\huge\bf\green {Hey \: there!}$



▶ Given :



α and β are the zeroes of the polynomial 3x^2 - 2x - 7



▶To Find :



α / β + β / α



▶ We know that :



Sum of zeroes = - coefficient of x / coefficient of x^2


=> α + β = - ( - 2 ) / 3


=> α + β = 2 / 3



Product of zeroes = constant term / coefficient of x^2


=> αβ = - 7 / 3



α / β + β / α = ( α )^2 + ( β )^2 / αβ


=> α / β + β / α = ( α + β )^2 - 2αβ / αβ


=> α / β + β / α = ( 2 / 3 )^2 - 2 × - 7 / 3 / - 7 / 3


=> α / β + β / α = 4 / 9 + 14 / 3 / - 7 / 3


=> α / β + β / α = 4 + 42 / 9 / - 7 / 3


=> α / β + β / α = 46 / 9 / - 7 / 3


=> α / β + β / α = 46 / 9 × - 3 / 7


=> α / β + β / α = - 46 / 21



$\large{\boxed {\boxed {\pink {\sf {Therefore, {\dfrac { \alpha}{ \beta}} +{ \dfrac {\beta}{ \alpha}}= { \dfrac{ - 46}{21}}}}}}}$


✔✔ Hence, it is solved ✅✅




$\mathbb {\huge {\fcolorbox{yellow}{green}{Hope It Helps}}}$




$\huge\bf\red {\#BeBrainly}$