Math, asked by justified, 22 days ago

25. Rivana is going for adventure trip with his friends. They want to make a tent house with equilateral triangular face. If the length of one dimension of tent house is 12 m, then what will be the length of the rod they will put at mid of the equilateral triangular face.
(A) 4/3 m (B) 673 m (C) 573 m (D) 773 m
Please tell me the answe ASAP

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Answers

Answered by madhav127
9

Answer:

hey mate here is ur ans

Step-by-step explanation:

hope it help u

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Answered by rahul123437
1

Triangle

Given

Face of tent house is like equilateral triangle.

Dimension of equilateral face is 12m.

To find:

The length of rod which they will put at the mid of the equilateral triangular face.

Explanation:

A figure showing the actual question condition is attached.

Pythagoras Theorem:

It states that the sum of squares of the lengths of the two short sides of the right triangle is equal to the square of the length of the hypotenuse.

It can be written as a^2 + b^2 = c^2.

Area of Triangle =\frac{1}{2}  \times base \times height\\Here, base = 6cm \\and height= h cm \\Now, apply Pythagoras Theorem in the triangle.12^2 = h^2 + (6)^2\implies h^2 = 12^2 - (6^2)\implies h^2 = 108Or, h = \sqrt[2]{108} \\\implies h=6\sqrt{3}

Hence , height of rod will be 6\sqrt{3} m.

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