Question

25. Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity (u) and the braking capacity, or deceleration,. A car travelling at speed 72km/hr suddenly applies the brake with the deceleration of 5m/s2 . Find the stopping distance of the car​

Answer 1

$\huge \underline \mathrm \purple{Question↣}$

sᴛᴏᴘᴘɪɴɢ ᴅɪsᴛᴀɴᴄᴇ ᴏғ ᴠᴇʜɪᴄʟᴇs : ᴡʜᴇɴ ʙʀᴀᴋᴇs ᴀʀᴇ ᴀᴘᴘʟɪᴇᴅ ᴛᴏ ᴀ ᴍᴏᴠɪɴɢ ᴠᴇʜɪᴄʟᴇ, ᴛʜᴇ ᴅɪsᴛᴀɴᴄᴇ ɪᴛ ᴛʀᴀᴠᴇʟs ʙᴇғᴏʀᴇ sᴛᴏᴘᴘɪɴɢ ɪs ᴄᴀʟʟᴇᴅ sᴛᴏᴘᴘɪɴɢ ᴅɪsᴛᴀɴᴄᴇ. ɪᴛ ɪs ᴀɴ ɪᴍᴘᴏʀᴛᴀɴᴛ ғᴀᴄᴛᴏʀ ғᴏʀ ʀᴏᴀᴅ sᴀғᴇᴛʏ ᴀɴᴅ ᴅᴇᴘᴇɴᴅs ᴏɴ ᴛʜᴇ ɪɴɪᴛɪᴀʟ ᴠᴇʟᴏᴄɪᴛʏ (ᴜ) ᴀɴᴅ ᴛʜᴇ ʙʀᴀᴋɪɴɢ ᴄᴀᴘᴀᴄɪᴛʏ, ᴏʀ ᴅᴇᴄᴇʟᴇʀᴀᴛɪᴏɴ,. ᴀ ᴄᴀʀ ᴛʀᴀᴠᴇʟʟɪɴɢ ᴀᴛ sᴘᴇᴇᴅ 72ᴋᴍ/ʜʀ sᴜᴅᴅᴇɴʟʏ ᴀᴘᴘʟɪᴇs ᴛʜᴇ ʙʀᴀᴋᴇ ᴡɪᴛʜ ᴛʜᴇ ᴅᴇᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴏғ 5ᴍ/s² . ғɪɴᴅ ᴛʜᴇ sᴛᴏᴘᴘɪɴɢ ᴅɪsᴛᴀɴᴄᴇ ᴏғ ᴛʜᴇ ᴄᴀʀ.

$\huge \underline \mathrm \green{Answer↣}$

Here $\bold{u \: =72 km/hr = \frac {72×1000}{3600} m/s \: =20 m/s }$

$\bold{v\: =0}$

$\bold{a = -5 m/s^2}$

Now using the relation ;

$\boxed {\bold{v^2=u^2+2as}}$

$\implies \bold {0=(20)2+2×(−5)×s}$

$\bold{\red{\implies s=40m}}$

ʜᴇɴᴄᴇ , sᴛᴏᴘᴘɪɴɢ ᴅɪsᴛᴀɴᴄᴇ ᴏғ ᴛʜᴇ ᴄᴀʀ = 40ᴍ

Answer 2

$\huge{\orange{\underline{\purple{\mathscr{Solution}}}}}$

✷ An atom can take part in a chemical reaction...

✷ Full form of Bec - Bose - Einstein Condensate...

✷ It is more compressible - Gases..

Michael was shocked by the news of the miracle recovery for he thought that Sebastian Shultz couldn’t be the boy he had met. Six weeks ago he was badly injured in a motorway accident, his condition in the hospital was described as critical though stable. Sebastian didn’t regain consciousness. His parents were informed that the boy was in a coma.