25. Suppose two students are trying to make a new measurement
system so that they can use it like a code measurement
system and others do not understand it. Instead of taking
1 kg, 1 m and 1 sec as basic units they took unit of mass
as a kg, the unit of length as B m and unit of time as y
second. They called power in new system as ACME.
I'll mark you as brainliest
Answers
Given: Instead of taking 1 kg, 1 m and 1 sec as basic units they took unit of mass as a kg, the unit of length as b m and unit of time as y second.
To find: 1 N in new system and 1 J in new system.
Solution:
- Now we have given that instead of taking 1 kg, 1 m and 1 sec as basic units they took unit of mass as a kg, the unit of length as b m and unit of time as y second.
- Consider 1 N, we write it as:
1 N = mass x acceleration
1 N = kg x m/s^2
- Now according to new system, we have:
1 N = (kg'/a x m'/b ) / (s')^2/r^2
1 N = ( a^-1 x b^-1 x r^2 ) x kg'm'/(s')^2
- New system will be: a^-1 x b^-1 x r^2
- Consider 1 J, we write it as:
1 J = kg x m^2/s^2
- Now according to new system, we have:
1 N = (kg'/a x (m')^2/b^2 ) / (s')^2/r^2
1 N = ( a^-1 x b^-2 x r^2 ) x kg'(m')^2/(s')^2
- New system will be: a^-1 x b^-2 x r^2
Answer:
So 1 N in new system will be a^-1 x b^-1 x r^2 and 1 J in new system will be a^-1 x b^-2 x r^2 .
Answer:
below:
Explanation:
I am also a student i am not sure about my answer but i will try the 2023 jee batch, 1KG=alpha
then 1=alpha/kg
or 1=kg/alpha (means either you write q/p or p/q both are same if the result is one)
now why i reversed it obviously to make it more like a newton
same again 1M=bita
then 1=bita/metre
or 1=metre/beta explained earlier
again this time we want time as a denominator so we won't change
1 sec=Gamma
1=Gamma/sec
force=[M1L1T-2]
=kg/alpha*metre/bita*(gamma/second)^2
=(kg*metre*gamma^2) /(alpha *bita*second^2)
=kg m/sec^-2 *gamma^2 alpha^-1 bita ^-1
=newton gamma^2 alpha ^-1 bita ^-1 : kg m/sec^-2==newton
=so for 1 newton alpha is -1 bita is -1 gamma is 2