Question

(25*t^-4)/(5^3*10*t^-8) ​

Answer 1

$Given \: \frac{(25\times t^{-4})}{(5^{3} \times 10 \times t^{-8})}$

$=\frac{5^{2} t^{-4+8}}{5^{3}\times 2\times 5 }$

$\boxed{\pink{ Since, \frac{a^m}{a^n} = \frac{1}{a^{n-m}} }}$

$= \frac{t^{4}}{5^{3+1-2}\times 2 }$

$= \frac{t^{4}}{5^{2} \times 2 }$

$= \frac{t^{4}}{50}$

Therefore.,

$\red{Value \:of \: \frac{(25\times t^{-4})}{(5^{3} \times 10 \times t^{-8})}}$

$\green {=\frac{t^{4}}{50}}$

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Answer 2

${lgathered}Given \: [tex]\frac{(25\times t^{-4})}{(5^{3} \times 10 \times t^{-8})}$=$\frac{5^{2} t^{-4+8}}{5^{3}\times 2\times 5 }$= \frac{t^{4}{5^{3+1-2}\times 2 }\\$= [tex]\frac{t^{4}}{5^{2} \times 2 }$=$\frac{t^{4}}{50}\end{lgathered}$

Therefore.,

$\red{Value \:of \: \frac{(25\times t^{-4})}{(5^{3} \times 10 \times t^{-8})}}\green {=\frac{t^{4}}{50}}$