Math, asked by Khaan00, 6 months ago

25 × t^-4 / 5^-3 × 10 × t^-8(t≠0)

Answers

Answered by Anonymous
14

⟹ \frac{25  \: \times \:  t {}^{ - 4} }{5 {}^{ - 3 }  \times  \: 10 \:  \times  \: t {}^{ - 8} }    \\⟹ \frac{25 \:  \times  \:  \frac{1}{t {}^{ 4} } }{ \frac{1}{5 {}^{3} } \:  \times 10 \times  \frac{1}{t }{ {}^{8} } }  \\  ⟹\frac{ \frac{25}{t {}^{4} } }{ \frac{1}{125  \:  \times  \: 10 \:   \times  \:  \frac{1}{t {}^{8} } } }  \\ ⟹ \frac{ \frac{25}{t {}^{4}  {} } }{ \frac{2}{25 \:  \times  \frac{1}{t {}^{8} } } }  \\ ⟹ \frac{ \frac{25}{t {}^{4} } }{ \frac{2}{25t {}^{8} } }  \\⟹ \frac{25}{t {}^{4} }   \times  \frac{25t {}^{8} }{2}  \\ ⟹ \frac{625}{2} t {}^{8 - 4}  =  \frac{625}{2} t {}^{4}

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Answered by Kdkfkd
0

25 × t^-4 / 5^-3 × 10 × t^-8(t≠0)

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