Question

25×t^−4/5−3 × t^-8 tell fast in steps on notebook req pls for exam now

Answer 1

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Answer 2

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$\frac{25 \times {t}^{ - 4} }{ {5}^{ - 3} \times1 0 \times {t}^{ - 8} } \\ = \frac{25 \times {5}^{3} \times {t}^{ - 4 - ( - 8)} }{10} \\ = \frac{5 \times {5}^{3} \times {t}^{ - 4 + 8} }{2} \\ = \frac{ {5}^{4} \times {t}^{4} }{2} \\ = \frac{ {(5 + t)}^{4} }{2} (ans)$

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