Question

25. The CFSE for a low- spin octahedral complex of d7' ion is
a) 2.4 ∆0. b) - 1.8 ∆0 c)1.2 ∆0. d) -0.6 ∆0.​

Answer 1

Explanation:

1.2 ∆0

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Answer 2

Given:

$d^7$.

To find:

We have to find its CFSE in a low spin.

Solution:

$d^7$ ion on a low spin split as above.

Here $t_{2g}$ have a total of 6 electrons and $e_g$ have a total of 1 electron.

Energy contribution for 1 electron in $t_{2g}$ is -0.4∆o.

Energy contribution for an electron in $t_{2g}$ is -0.4×6=-2.4∆o.

Energy contribution for 1 electron in $e_{g}$ is +0.6∆o.

Thus CFSE=-2.4+0.6∆o

CFSE=-1.8∆o.

Thus, the CFSE for $d^7$ ion is -1.8∆o.

Hence the correct option is b.