Math, asked by meghanabandaru333, 10 months ago

25. The least possible number which when successively
divided by 10, 7 and 6 leaves remainders of 8, 4 and 5
respectively is
(A) 256 (B) 148 (C) 398 (D) 198
- 2011

Answers

Answered by sawarnjasvir

Answer:

Let the quotient be q when divided by 8. n = 3(5(8q + 7) + 4) + 1 = 3(40q + 39) + 1 = 120q + 117 + 1 = 120q + 118. Now , if it is divided by 8. We have ...

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25. The least possible number which when successivelydivided by 10, 7 and 6 leaves remainders of 8, 4 and 5respectively is(A) 256 (B) 148 (C) 398 (D) 198- 2011​

Answers

25. The least possible number which when successively
divided by 10, 7 and 6 leaves remainders of 8, 4 and 5
respectively is
(A) 256 (B) 148 (C) 398 (D) 198
- 2011