Question

25. The length. breadstrand height of a room are 5m. 4m and 3m respectively. Find the diagonal of the
room​

Answer 1

Answer:

$\boxed{\sf Diagonal \ of \ the \ box = 5\sqrt{2}}$

Given:

Length (l) = 5 m

Breadth (b) = 4 m

Height (h) = 3 m

To Find:

Diagonal of the room

Step-by-step explanation:

$\sf Diagonal \ of \ Cuboid = \sqrt{Length^{2} + Breadth^2 + Height^2} \\ \\ \sf = \sqrt{ {5}^{2} + {4}^{2} + {3}^{2} } \\ \\ \sf = \sqrt{25 + 16 + 9} \\ \\ \sf = \sqrt{50} \\ \\ \sf = \sqrt{ {5}^{2} \times 2} \\ \\ \sf = \sqrt{ {5}^{2} } \times \sqrt{2} \\ \\ \sf = 5 \sqrt{2} \: cm$