Question

25. The number of atoms in 4.25 g of N3 is approximately
(a) 1 x 1023
(c) 4 x 1023
(b) 2 x 1023
(d) 6 x 1023​

Answer 1

Answer:

a) is correct option

Explanation:

42g of N3 has 6.022×10^23 N-atoms

4.25g of N3 has( 6.022×10^23N-atoms/42)×4.25

= 6.022×10^23 N-atoms