Math, asked by affu5557, 7 months ago

25. The present age of a father is 3 yr
than three times the age of his son.
three years later, father's age will be 10 yr
than twice the age of the son. The father
present age is
(a) 33yr
(b) 39yr
(c) 40yr.

(c) 45 yr​

Answers

Answered by P1Gt3sa777
0

Answer:

33 years is the answer part a

Answered by Anonymous
9

Answer:

(a) 33 years

Step-by-step explanation:

Assume that the present age of father be x years and son be y years.

The present age of a father is 3 years more than three times the age of his son.

→ x = 3y + 3 ...................(1)

Three years later, father's age will be 10 year than twice the age of the son.

3 years later:

  • Age of father = (x + 3) years
  • Age of son = (y + 3) years

As per given condition,

→ x + 3 = 2(y + 3) + 10

→ 3y + 3 + 3 = 2y + 6 + 10 [From (1)]

→ 3y + 6 = 2y + 16

→ y = 10

Substitute value of y in (1)

→ x = 3(10) + 3

→ x = 33

Hence, the present age of father is 33 years and son is 10 years.

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