Question

25. The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair.
Find the cost of each​

Answer 1

Let,cost of one chair be x

cost of one table will be x+40

Then,

cost of 2 tables + cost of 3 chairs = 360

2(x+40)+x=360

2x+80+x=360

3x+80=360

3x=360-80

3x=240

x=240/3

x=80

Therefore,

Cost of 1 chair = 80

Cost of 1 table = 120

Answer 2

${ \sf{ \underline{ \red{ \underline{Question}}}} : - }$

• The price of 2 tables and 3 chairs is 360, but a table costs 40 more than the chair. Find the cost of each ?

${ \sf{ \underline{ \red{ \underline{Given}}}} : - }$

• a) The price of 2 tables and 3 chairs is 360.
• b) A table costs 40 more than the chair.

${ \sf{ \underline{ \red{ \underline{Solution}}}} : - }</p><p></p><p>$

{ According to question & given }

• Let, x be the cost of table & y be the cost of chair .

Hence, { From ( a ) }

• 2x + 3y = 360 ...... ( 1 )

{ From given ( b ) }

• x = y + 40 ...... ( 2 )
• x - y = 40 ...... ( 3 )

Multiply eq. ( 3 ) by 2

• 2x - 2y = 80 ...... ( 4 )

Subtract eq. ( 4 ) eq. ( 1 )

2x + 3y = 360

- ( 2x - 2y = 80 )

__________________

5y = 280

y = 280/5

y = 56

Put value of y in eq. ( 2 )

• x = y + 40
• x = 56 + 40
• x = 96

Hence cost of one table is unit 96 & cost of one chair is unit 56.