Question

25. The sum of 5 consecutive natural numbers is
325. Find the numbers. ​

Answer 1

Answer:

the no are 63,64,65,66,67.

Step-by-step explanation:

1 no=a

2 no=a+1

3 no=a+2

4 no=a+3

5no=a+4

their sum=325

then,

a+a+1+a+2+a+3+a+4=325

5a+10=325

5a=325-10=315

5a=315

a=315/5=63

a=63.

a+1=64,a+2=65,a+3=66,a+4=67.

you can verify it by adding all these no.

Answer 2

Answer:
Let the first consecutive natural number be “x”
The second consecutive natural no. be “x+1”
The third consecutive natural no. be “x+1+1” = “x+2”
The fourth consecutive natural no. be “x+1+1+1” = “x+3”
And the fifth consecutive natural no. be “x+1+1+1+1” = “x+4”

According to the question,

x + (x+1) + (x+2) + (x+3) + (x+4) = 325

x + x + 1 + x + 2 + x + 3 + x + 4 = 325

5x + 10 = 325

5x = 325 - 10

5x = 315

x = 315/5

x = 63



Therefore,
1st natural no. = x = 63
2nd consec. natural no. = x + 1 = 63 + 1 = 64
3rd con. natural no. = x + 2 = 63 + 2 = 65
4th con. natural no. = x + 3 = 63 + 3 = 66
And, 5th con. natural no.= x + 4 = 63 + 4 = 67


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