25. The terminal voltage of a battery is 14 V at
no load. When the battery is supplying 100 A
of current to a load the terminal voltage drops
to 12 V. Then the source impedance is
1) 0.2 12
2) 1.4 12
3) 1.2.2
4) ΟΩ
26
A 50
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Answer
20=1.8(10+r)
20/1.8=10+r
20/1.8–10=r
r=20/1.8–10
=(20–18)/1.8
internal resistance=1.1 Ohm.
Explanation:
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